Here we have,
x→∞limsn+1sn−1=0 ⇒x→∞limsn+1sn+1−2=0 ⇒x→∞lim(1−sn+12)=0 ⇒1−x→∞limsn+12=0 ⇒x→∞limsn+11=21
Now, as this is an equality and RHS is finite, we can be sure that x→∞limsn is some value let say c∈R .
i.e. c=x→∞limsn
Therefore,
c+11=21 ⇒c+1=2 ⇒c=1 So, we have:-
x→∞limsn=1
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