Answer to Question #159444 in Calculus for ary

Question #159444

find "y'" for each:

1. "y= sin x - cos x"

2. "y= tan x \/ (x+1)"

3."y=sin (\u03c0\/4)"

Expert's answer

yʼ = sin(x) + cos(x)
yʼ = "\\frac{(x+1)sec^2(x) - tan(x)}{(x+1)^2}"
y' = 0

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