Question #159450

find yy' for each:

1. y=x3sinxy= x³ sin x

y=x2+2xcosxy= x² + 2x cos x2. y=x2+2xy= x² + 2x cosxcos x

3.y=x/(secx+1)y = x/( sec x + 1)

y=x2+2xcosxy= x² + 2x cos x

1
Expert's answer
2021-02-02T01:32:05-0500

1) y=3x2sinx+x3cosxy'=3x^2\sin x+x^3\cos x

2) y=2x+2cosx2xsinxy'=2x+2\cos x-2x\sin x

3) y=secx+1xtanxsecx(secx+1)2y'=\frac{\sec x +1-x\tan x\sec x}{(\sec x+1)^2}


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