find the slope of the tangent line to f(x)=x2 + 2x at x=3
Solution:
Given: "f(x)=x^2+2x" ...(i)
Slope of tangent is "f'(x)"
So, we find derivative of given "f(x)"
On differentiating (i) w.r.t "x"
"f'(x)=2x+2"
Putting "x=3" in "f'(x)" , we get,
"f'(3)=2(3)+2=6+2=8"
Answer: 8
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