Question #151570

Find the volume generated by revolving the area bounded by y=e^x, x=1, x=0, about y-axis. Sketch the curve indicating the generating area.

Expert's answer

y=ex,x=0,x=1y=e^x, x=0, x=1

V=∫012πx(ex)dxV=\displaystyle\int_{0}^12\pi x(e^x)dx

∫xexdx\displaystyle\int xe^xdx


∫udv=uv−∫vdu\int udv=uv-\int vdu

u=x,du=dxu=x, du=dx

dv=exdx,v=∫exdx=exdv=e^xdx, v=\displaystyle\int e^xdx=e^x


∫xexdx=xex−∫exdx=xex−ex+C\displaystyle\int xe^xdx=xe^x-\displaystyle\int e^xdx=xe^x-e^x+C

V=∫012πx(ex)dx=2π[xex−ex]10V=\displaystyle\int_{0}^12\pi x(e^x)dx=2\pi\big[xe^x-e^x\big]\begin{matrix} 1 \\ 0 \end{matrix}

=2π(e−e−(0−1))=2π(units3)=2\pi(e-e-(0-1))=2\pi (units^3)

V=2π cubic unitsV=2\pi\ cubic\ units



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