Question #117085

The cost (in dollars) of producing x units of a certain commodity is C(x)=500+10x+0.05x^2


I) find the average rate of change of C with respect x when the production level is from x=100 to x=105 units

ii) find the instantaneous rate of change of C with respect to x=100

Expert's answer

Given C(x)=500+10x+0.05x2C(x)=500+10x+0.05x^2

i) The average rate of change is the change in yy value over the change in xx value for two distinct points, hence if xx changes from 100 to 105, then you may evaluate the average rate of change of C(x)C(x)  such that: C(105)C(100)105100\frac{C(105)-C(100)}{105 - 100 } .

Now, C(105)C(100)=(500+10(105)+0.05(105)2)(500+10(100)+0.05(100)2)=(10501000)+(551.25500)=101.25C(105)-C(100) = (500 + 10(105) + 0.05 (105)^2) - (500 + 10(100) + 0.05 (100)^2) = (1050 - 1000) + (551.25 - 500) = 101.25

So, Average rate of change of C(x)C(x) from 100 to 105 is 101.255=20.25\frac{101.25}{5} = 20.25.


ii)  The instantaneous rate of change of CC with respect to x=100 is C(x)x=100C'(x)|_{x=100} .

Now, given C(x)=500+10x+0.05x2C(x)=500+10x+0.05x^2

    C(x)=10+0.1x\implies C'(x) = 10 + 0.1 x

The instantaneous rate of change of CC with respect to 100 is C(100)=10+0.1(100)=20C'(100) = 10 + 0.1(100) = 20 .


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