Consider fff on S=(0,+∞)×(0,+∞)×(−∞,0)S=(0,+\infty)\times(0,+\infty)\times(-\infty,0)S=(0,+∞)×(0,+∞)×(−∞,0).
We have f(x,y,z)=x+y−zf(x,y,z)=x+y-zf(x,y,z)=x+y−z on SSS.
So fff is differentiable on SSS. Since SSS is an open set, and (2,3,−1)∈S(2,3,-1)\in S(2,3,−1)∈S, we obtain that fff is differentiable at (2,3,−1)(2,3,-1)(2,3,−1)
Answer: fff is differentiable at (2,3,−1)(2,3,-1)(2,3,−1)
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