Answer to Question #107182 in Calculus for Nikesh gautam pandit ji

Question #107182
Check whether the function
f(x,y)= { 4x^2y/4x^4+y^2,. (x,y)not=to(0,0)
0 (x,y) = to (0,0)}

is continuous at ( 0,0).
1
Expert's answer
2020-04-02T06:36:12-0400

lim(x;y)(0;0)4x2y4x4+y2=[y=x2]==limx04x2x24x4+x4=450=f(0,0)\lim\limits_{(x;y)\to (0;0)}\frac{4x^2y}{4x^4+y^2}=[y=x^2]=\\=\lim\limits_{x\to 0}\frac{4x^2x^2}{4x^4+x^4}=\frac{4}{5}\ne0=f(0,0)

Therefore the function f(x,y)f(x,y) is not continuous at ( 0,0).


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