The given function is
f(x,y)=(y+x)(y−x)(1+y2)(1+x2)
The repeated limits of f(x,y) are following:
limx→0(limy→0 f(x,y))=limx→0(−1)(1+x2)
=−1
limy→0(limx→0 f(x,y))=limy→0(1+y21)
=1
Simultaneous limit of f(x,y) at (0,0) does not exist because repeated limits are not equal.
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