Question #105387
Compute fxy and fyx for the function f (x,y)=e^x+y sinx +9x^2+2y at (1,2)
1
Expert's answer
2020-03-16T13:38:30-0400

f(x,y)=ex+ysinx+9x2+2yf (x,y)=e^x+y sinx +9x^2+2y

fxy=(fx)y=y(fx)f_{xy}=(f_x)_y= \frac{\partial }{\partial y}(\frac{\partial f}{\partial x})

=y(ex+ycosx+18x)=\frac{\partial }{\partial y}(e^x+ycosx+18x)

=cosx=cosx

Thus, fxy(1,2)=cos(1)f_{xy}(1,2)=\cos(1)


fyx=(fy)x=x(fy)f_{yx}=(f_y)_x= \frac{\partial }{\partial x}(\frac{\partial f}{\partial y})

=x(sinx+2)=\frac{\partial }{\partial x}(sinx+2)

=cosx=cosx

Thus, fyx(1,2)=cos(1)f_{yx}(1,2)=cos(1)



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