Question #104212
Derive the expression for electric potential due a uniformly charged spherical
shell at a point outside the shell.
1
Expert's answer
2020-04-21T07:57:02-0400

Let, R be the radius of the shell and Q be the charge uniformly distributed on the surface.

i) For a point outside the shell :

By Gauss's law, E.4πr2=Qen/ϵ0E.4πr ^ 2 = ​ Q _{ en}/\epsilon_0 ​

here r be the distance from centre of shell (r>R) and charge enclosed by surface Qeq=Q.Qeq ​=Q.

So, the electic field outside the shell is  E=Qen/(4πr2ϵ0)E = ​ Q _{ en}/(4πr^2\epsilon_0) , the electric potential outside the shell is V(r)=rQen4πr12ϵ0dr1=Qen4πrϵ0.V(r)=-\int_{\infin}^r \frac{Q_{en}}{4\pi r_1^2 \epsilon_0}d r_1=\frac{Q_{en}}{4\pi r\epsilon_0}.


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Comments

Assignment Expert
19.04.20, 21:45

Dear Awesh, thank you for correcting us.

Awesh
19.04.20, 21:22

Totally wrong... According to question find 'Electric Potential' ("V")... But in the solution the expert has found 'Electric Field' ("E").

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