let's find a first derivative
y′=(sin(x5))′=(sin(x5))′∗(x5)′=5∗x4∗cos(x5)
now we have to understand whether the graph y' increasing or decreasing. So let's find the value of the derivative y' at x=13
y′=5∗x4∗cos(x5)=5∗134∗cos(135)=106353⟹y′>0 ,
so the graph is increasing at x=13.
Next question - is the graph concave up or concave down. Let's find second derivative y"
y′′=(sin(x5))′′=(5∗x4∗cos(x5))′=(x4)′∗cos(x5)+x4∗(cos(x5))′=4∗x3∗cos(x5)+x4∗(−5∗x4∗sin(x5))=−25∗x8∗sin(x5)+20∗x3∗cos(x5)
to understand is the graph concave up or concave down let's find y'' at x=13
y′′=−25∗x8∗sin(x5)+20∗x3∗cos(x5)=5∗x3∗(4∗cos(x5)−5∗x3∗sin(x5))
y′′=−13609384564.031⟹y′′<0
so the graph is concave down
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