Sequence "A_n" is convergent if and only if for every "\\varepsilon >0" there is a natural number N such that "|A_n-A_{n+p}|<\\varepsilon" for all "n>N" and natural number "p"
The sequence "A_n=1\/2n", then for each "\\varepsilon" let's take the nearest natural number "N\\geqslant(1\/2\\varepsilon)" , hence
take a look at "|A_n-A_{n+p}|: 0<A_{n+p}<A_n, \\,then\\, |A_n-A_{n+p}|<A_n,"
"|A_{n+p}-A_n|<A_n=1\/2N<1\/(2*1\/\\varepsilon)=\\varepsilon\/2<\\varepsilon"
finally
"|A_{n+p}-A_n|<\\varepsilon". Thus, the sequence "A_n" is convergent by Cauchy’s general principle of convergence.
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