Question #103845
Cauchy’s general principle of convergence for sequences. To check whether the
sequence (1/2n)
is convergent or not.
1
Expert's answer
2020-03-19T19:06:34-0400

Sequence AnA_n is convergent if and only if for every ε>0\varepsilon >0  there is a natural number N such that AnAn+p<ε|A_n-A_{n+p}|<\varepsilon for all n>Nn>N and natural number pp


The sequence An=1/2nA_n=1/2n, then for each ε\varepsilon let's take the nearest natural number N(1/2ε)N\geqslant(1/2\varepsilon) , hence

take a look at AnAn+p:0<An+p<An,thenAnAn+p<An,|A_n-A_{n+p}|: 0<A_{n+p}<A_n, \,then\, |A_n-A_{n+p}|<A_n,

An+pAn<An=1/2N<1/(21/ε)=ε/2<ε|A_{n+p}-A_n|<A_n=1/2N<1/(2*1/\varepsilon)=\varepsilon/2<\varepsilon

finally

An+pAn<ε|A_{n+p}-A_n|<\varepsilon. Thus, the sequence AnA_n is convergent by Cauchy’s general principle of convergence.






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