Question #103844
All strictly monotonically decreasing sequences are convergent.

True or false
1
Expert's answer
2020-03-02T09:57:13-0500

False. A sequence {an}nN\{a_n\}_{n\in \mathbb{N}} is called strictly monotonically decreasing if and only if an+1<ana_{n+1} < a_n for all nNn\in \mathbb{N}. Since (n+1)=n1<n-(n+1) = -n-1 < -n, the sequence {n}nN\{-n\}_{n\in \mathbb{N}} satisfies this definition and is strictly monotonically decreasing. Assume that it converges to some aRa\in \mathbb{R}. Then there is n0Nn_0\in \mathbb{N} such that a1<m<a+1a-1 < -m < a+1 for all mn0m\geq n_0. By the Archimedean property of the real numbers, there is n1Nn_1\in \mathbb{N} such that n1a1-n_1 \leq a-1. Letting n2=max(n0,n1)n_2 = \operatorname{max}(n_0, n_1), we have that a1<n2a-1 < -n_2 and n2a1-n_2 \leq a-1, a contradiction. Therefore, {n}nN\{-n\}_{n\in \mathbb{N}} is not convergent.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS