Answer to Question #102273 in Calculus for Nimra

Question

f(x)=cotx+tanx²-2cosx²

Answer 1

$\frac{df}{dx}=-\frac{1}{sin^2(x)}+\frac{2x}{cos^2(x^2)}-2\cdot (-sin(x^2)\cdot 2x)=$

$=-\frac{1}{sin^2(x)}+\frac{2x}{cos^2(x^2)}+4xsin(x^2)$