Volume flow rate of water flowing in the pipe Q = ππ/ππ‘ [m^3/ h] varies with time as follows: Q (t) = 5 + 2cos^2 (Οt/12). How many cubic meters of water is flowing through the pipe through the day? (the unit of time is an hour)
Since "\\frac{dV}{dt}=Q" , we can calculate V as
"V=\\int\\limits_0^{24}Q(t)dt=\\int\\limits_0^{24}(5+2cos^2\\frac{\\pi t}{12}dt)=\\left(5t+t+\\frac{6sin\\frac{\\pi t}{6}}{\\pi}\\right)_0^{24}=144"
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