Question #101193
Using the mathematical model: to calculate velocity of a car accelerating from rest in straight line. Equation is v(t) = A (1-e ^ -t/t max speed) the ^ means to the power of. v(t) is the instantaneous velocity of the car (m/s), t is the time in seconds, tmaxspeed is the time to reach the maximum speed in seconds and A is a constant. Find out how to 1. Create a graph of position vs time for the given model? 2. Derive an equation a(t) for the instantaneous acceleration of the car as a function of time. Identify the acceleration of the car at t=0s? and asymptote of this function as t ⮕ ∞?
1
Expert's answer
2020-01-12T13:50:11-0500

We are given velocity as a function of time so integrating it with respect to time we will get he equation of displacement with respect to time

v(t)=A(1et/tmax)v(t)=A(1-e^{-t/t_{max}})

dx=A(1et/tmax)dt\intop{dx}=\intop A(1-e^{-t/t_{max}})dt

x(t)=Ax(t)=A tt +A(et/tmax)tmax+A(e^{-t/t{max}})t_{max}

graph of the above function will be a linear one as e-t/tmax will be almost equal to zero




Differentiating velocity with respect to time we will get the acceleration

a(t)=da(t)=d (A(1et/tmax))/dt(A(1-e^{-t/t_{max}}))/dt

a(t)=Aet/tmax/tmaxa(t)=Ae^{-t/t_{max}}/t_{max}

at t=0

acceleration= A/tmax

and as we tend towards infinity we see that the value of acceleration tends to become closer to zero hence the asymptote of this function is x-axis or a=0



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