Answer to Question #101193 in Calculus for Leo

Question #101193
Using the mathematical model: to calculate velocity of a car accelerating from rest in straight line. Equation is v(t) = A (1-e ^ -t/t max speed) the ^ means to the power of. v(t) is the instantaneous velocity of the car (m/s), t is the time in seconds, tmaxspeed is the time to reach the maximum speed in seconds and A is a constant. Find out how to 1. Create a graph of position vs time for the given model? 2. Derive an equation a(t) for the instantaneous acceleration of the car as a function of time. Identify the acceleration of the car at t=0s? and asymptote of this function as t ⮕ ∞?
1
Expert's answer
2020-01-12T13:50:11-0500

We are given velocity as a function of time so integrating it with respect to time we will get he equation of displacement with respect to time

"v(t)=A(1-e^{-t\/t_{max}})"

"\\intop{dx}=\\intop A(1-e^{-t\/t_{max}})dt"

"x(t)=A" "t" "+A(e^{-t\/t{max}})t_{max}"

graph of the above function will be a linear one as e-t/tmax will be almost equal to zero




Differentiating velocity with respect to time we will get the acceleration

"a(t)=d" "(A(1-e^{-t\/t_{max}}))\/dt"

"a(t)=Ae^{-t\/t_{max}}\/t_{max}"

at t=0

acceleration= A/tmax

and as we tend towards infinity we see that the value of acceleration tends to become closer to zero hence the asymptote of this function is x-axis or a=0



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS