Question #300805

Find an equation of the ellipse having a major axis of length 10 and foci at , (1,−2 )and , (−7,−2.)


1
Expert's answer
2022-02-22T13:42:51-0500

The equation of an ellipse is

(xh)2a2+(yk)2b2=1,\frac{\left(x - h\right)^{2}}{a^{2}} + \frac{\left(y - k\right)^{2}}{b^{2}} = 1,

where (h,k)\left(h, k\right) is the center, aa and bb are the lengths of the semi-major and the semi-minor axes.

Thus a=10/2=5.a=10/2=5.

From properties of an ellipse


k=2k=-2

(h1)2=a2b2(h-1)^2=a^2-b^2

(h+7)2=a2b2(h+7)^2=a^2-b^2

Then


(h1)2=(h+7)2(h-1)^2=(h+7)^2

h22h+1=h2+14h+49h^2-2h+1=h^2+14h+49

16h=4816h=-48

h=3h=-3

(31)2=52b2(-3-1)^2=5^2-b^2

b2=9b^2=9

The equation of the ellipse is


(x+3)225+(y+2)29=1,\frac{\left(x+3\right)^{2}}{25} + \frac{\left(y +2\right)^{2}}{9} = 1,


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