Answer to Question #300689 in Analytic Geometry for Bea Coleen

Question

2) C (3, -3), D (0, 4) Find the midpoints of the ff. Points 3) E (3, 2) , F (-1 , -2) 4) G (-3, 0), H (2, -1 ) 5) I (3, 1), J (-2, 0 )

Answer 1

2)

$$x_M=\dfrac{x_C+x_D}{2}=\dfrac{3+0}{2}=3/2$$

$$y_M=\dfrac{y_C+y_D}{2}=\dfrac{-3+4}{2}=1/2$$

$M(3/2, 1/2)$

3)

$$x_K=\dfrac{x_E+x_F}{2}=\dfrac{3-1}{2}=1$$

$$y_K=\dfrac{y_E+y_F}{2}=\dfrac{2-2}{2}=0$$

$K(1, 0)$

4)

$$x_N=\dfrac{x_G+x_H}{2}=\dfrac{-3+2}{2}=-1/2$$

$$y_N=\dfrac{y_G+y_H}{2}=\dfrac{0-1}{2}=-1/2$$

$N(-1/2, -1/2)$

5)

$$x_P=\dfrac{x_I+x_J}{2}=\dfrac{3-2}{2}=1/2$$

$$y_P=\dfrac{y_I+y_J}{2}=\dfrac{1+0}{2}=1/2$$

$P(1/2, 1/2)$