1.find an equation for the plane that passes through the origin (0,0,0) and is parall to the plane -x+3y-2z=6.
2.find the distance between the point (-1,-2,0) and the plane 3x-y+4z=-2.
3.find the components of a unit vector satisfying V.<3,-1>=0.
Q1. Since we need to find the plane which is parallel to the given plane . I can write it as,
Since planes are parallel so their normal vector will be parallel.
So the equation will be, where c is constant.
since, plane passes through origin, then
So, the equation will be,
Q2. Distance of the point from the plane is given by,
Simply putting values, we get, units.
Q3. Given condition is,
Let
Since,
.
So all values which satisfy the above condition are solutions of the V.
Then unit vector will be,
Since b = 3a, then,
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