Find the vector equation of the plane determined by the points (0,2,1),(2,1,0),(1,-1,0). Further, check whether the line r=(1+2α)I + (2-3α)j - (1+5α)k intersects this plane. If it intersects, find the point of intersection. If the line and plane do not intersects,find the equation of another line that intersects this plane
plane in parametric view
Plane:(0,2,1)+v(2-0,1-2,0-1)+u(1-0,-1-2,0-1)=(2v+u,2-v-3u,1-v-u)
1)1+2a=2v+u
2)2-3a=2-v-3u
3)-1-5a=1-v-u
3)2+5a=v+u
1)1+2a+2v+u=v+2+5a,v=-1-3a,u=3+8a
2)2-3a=2-(-1-3a)-3(3+8a),-3a=1-9+3a-24a ,-8=(24-3-3)a,a=-4/9.
line and plane intersect
point(1/9,10/3,11/9)
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