Denote the slope of the line segmentjoining pointsAandRbyARs,AandCbyACsandRandCbyRCsARsACsRCs=3−13−(−1)=24=2=3−(−2)3−1=52=−2−11−(−1)=3−2By the condition of perpendiicularity, if the slopeof two lines arem1andm2,they are said to be perpendicular ifm1m2=−1The mistake was that Angela mistakened−3for−2in calculating the slope of lineRCIf−2was replaced with−3,RCs=4−2=2−1RCswould have been2−1=ARs−1and as such,RCwould be perpendicular toARmaking the triangle a right-angled triangle.For triangleARCto be a right-angled triangle,one of the line segments joining the pointshas to be perpendicular to the other.ARsRCs=−1,ARsACs=−1,&ACsRCs=−1Therefore, since none of the slopes are oppositereciprocal of the other, the triangle isnot a right-angled triangle.
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