Distance of line from origin d=2
Since the required line is parallel to the line formed by joining P1(2,7)andP2(−3,−2) ,
There slope must be equal
Let m be the slope of required line
m=−3−2−2−7
=−5−9
so m=59
Let the equation of required line be
y=mx+c
y=59x+c
Rearranging the equation as,
9x−5y+5c=0
Distance from origin is given by,
d=92+(−5)2∣9×0+0×−5+5c∣
2=1065c
5c=2106
c=0.4106
So the equation of required line is
9x-5y+2106 =0
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