Question #114942
Give the equation of a conic which is symmetric to the line x+2 = 0.
1
Expert's answer
2020-05-18T19:56:49-0400

The equations of conic sections is simmetric to the line x+2=0x+2=0 is

a) Circle (x+2)2+(yk)2=r2(x+2)^2+(y-k)^2=r^2 center is (2,k),(-2,k), radius is rr

b) Ellipse (x+2)2a2+(yk)2b2=1\frac{(x+2)^2}{a^2}+\frac{(y-k)^2}{b^2}=1 center is (2,k)(-2,k) length of major axis is 2a2a , length of minor axis is 2b2b

c) Hyperbola (x+2)2a2(yk)2b2=1\frac{(x+2)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 center is (2,k)(-2,k) distance between the vertices is 2a2a

d) Parabola (x+2)2=4p(yk)(x+2)^2=4p(y-k) vertex is (2,k)(-2,k) , focus is (2,k+p)(-2,k+p) ,directrix is the line

y=kpy=k-p , axis is the line x=2x=-2


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