Question #104245
If P is a point on an ellipse with a focus F, then PF is always greater than PM,
where M is the foot of the perpendicular drawn from P to a directrix of the ellipse.
1
Expert's answer
2020-03-02T11:41:15-0500

The statement is false.

If F is a focus of the ellipse, P is a point on the ellipse and M is foot of perpendicular from P on the directrix of the ellipse.

Then the distances PM and PF form a known ratio, which is PF/PM=ePF/PM=e ;

where e is eccentricity of the ellipse     0<e<1\implies 0<e<1 .

Thus, 0<PF/PM<1    PF<PM0<PF/PM<1 \implies PF<PM .


Hence, PF is always less than PM.



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