Vectors of points A and B are 2i-3j+4k and 3i-7j+12k respectively. Find the length of AB and its direction cosines.
"\\bold {AB}=\\bold {OB}-\\bold {OA}"
"\\bold {AB}=3\\bold {i}-7\\bold {j}+12\\bold {k}-(2\\bold {i}-3\\bold {j}+4\\bold {k})""\\bold {AB}=\\bold {i}-4\\bold {j}+8\\bold {k}"
"AB=|\\bold{AB}|=\\sqrt{1^2+(-4)^2+8^2}=9""AB=9"
Direction cosines are
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