Question #102666
Vectors of points A and B are 2i-3j+4k and 3i-7j+12k respectively
1
Expert's answer
2020-02-10T09:41:54-0500

Vectors of points A and B are 2i-3j+4k and 3i-7j+12k respectively. Find the length of AB and its direction cosines.


OA=2i3j+4k,OB=3i7j+12k\bold {OA}=2\bold {i}-3\bold {j}+4\bold {k}, \bold {OB}=3\bold {i}-7\bold {j}+12\bold {k}

AB=OBOA\bold {AB}=\bold {OB}-\bold {OA}

AB=3i7j+12k(2i3j+4k)\bold {AB}=3\bold {i}-7\bold {j}+12\bold {k}-(2\bold {i}-3\bold {j}+4\bold {k})AB=i4j+8k\bold {AB}=\bold {i}-4\bold {j}+8\bold {k}

AB=AB=12+(4)2+82=9AB=|\bold{AB}|=\sqrt{1^2+(-4)^2+8^2}=9AB=9AB=9

Direction cosines are


19, 49, 89{1 \over 9},\ -{4 \over 9}, \ {8 \over 9}



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