A wedding planner caters for wedding receptions. He charges R960 for the use of the venue and R 260 per person for a meal.
Write a formula relating the cost of the function to the number of guests. Using your formula, evaluate the total cost for 120 people at the wedding.
solve the following using gaussian elimination method 2x + y + 3z = 4 x + y + 2z = 0 2x + 4y + 6z = -8
What is equation? does all the equation involve a variable? Give an example of equation with a variable in it and which doesn't have a variable in it.
Find the sums of the following fractions.
1. 1/4 + 1/8
2. 1/2 + 3/10
3. 5/12 + 1/4
4. 2/5 + 4/15
5. 2/3 + 7/15
6. 2/3 + 7/15
7. 8/21 + 3/7
Use any of the models( any of appendices 3.1 to 3.7) for representing fractions to find the sum of the following fractions:
a. 1/6 + 5/6
b. 1/5 + 3/5
c. 2/9 + 5/9
d. 1/8 + 2/8
e. 3/12 + 5/12
Write a short paragraph of about ten lines about your experiences of learning how to work with fractions when you were still at school
a. Arrange the following fractions from biggest to smallest: 5/8; 4/4; 2/6; 3/7; 1/2
b. Compare the following fractions according to the instruction Bellow:
The symbol: < means less then; the symbol > means greater than, and the symbol = means equal to
Fill, in<,> or =
a. 1/2 [ ] 1/3 b. 1/2 [ ] 2/6
c. 1/3 [ ] 3/6 d. 1/2 [ ] 2/3
e. 2/3 [ ] 1/6 f. 5/6 [ ] 2/3
g. 2/3 [ ] 6/6 h. 1/3 [ ] 4/6
I. 4/6 [ ] 1/2 j. 1/2 [ ] 3/3
k. 1/2 [ ] 1/6 l. 5/6 [ ] 1/2
if 2x+3=4.find x
When theTitanic sank in 1912,it weighed 52,310 tons.Its weight years after sinking satisfies the equation
weight = Ae-0.0023t a) How much does the Titanic weigh in 2021?
b) How many years from now will theTitanic weigh10%of its original weight – 5231 tons?
Marble Arch in London is a monument with three arches – one large and two smaller.
The smaller arches are each 3.66m high at their apex and 1.83 wide at the base.
By modelling these arches as parabolas, taking the bottom left point of the arch to be (0, 0), find an equation describing the arch.
When on parade, the highest point of the standard carried by a man on horseback is 2.8m above the ground. If the standard would pass 30cm horizontally from the left- most point of the arch, would it fit underneath?