Question #225964

Two different fruit juices are mixed together. 7 liters of the first fruit juice contains 60% apple juice, and 5 liters of the second fruit juice contains 30% apple juice. Find the percentage of the new mix that is apple juice.


1
Expert's answer
2021-08-16T09:41:07-0400

V1=7  lC1=60  %V_1=7 \;l \\ C_1 = 60 \; \%

Pure apple juice:

p1=7×0.60=4.2  lV2=5  lC2=30  %p1=5×0.30=1.5  lVtotal=7+5=12  lptotal=4.2+1.5=5.7  lp_1 = 7 \times 0.60 = 4.2 \;l \\ V_2 = 5\; l \\ C_2 = 30 \; \% \\ p_1 = 5 \times 0.30 = 1.5 \;l \\ V_{total} = 7+5= 12 \;l \\ p_{total} = 4.2+1.5=5.7 \;l

Proportion:

12 l – 100 %

5.7 l – x

x=5.7×10012=47.5  x=\frac{5.7 \times 100}{12}=47.5 \;% %

Answer: 47.5 %


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