Answer to Question #225964 in Algebra for bou

Question

Two different fruit juices are mixed together. 7 liters of the first fruit juice contains 60% apple juice, and 5 liters of the second fruit juice contains 30% apple juice. Find the percentage of the new mix that is apple juice.

Answer 1

$V_1=7 \;l \\ C_1 = 60 \; \%$

Pure apple juice:

$p_1 = 7 \times 0.60 = 4.2 \;l \\ V_2 = 5\; l \\ C_2 = 30 \; \% \\ p_1 = 5 \times 0.30 = 1.5 \;l \\ V_{total} = 7+5= 12 \;l \\ p_{total} = 4.2+1.5=5.7 \;l$

Proportion:

12 l – 100 %

5.7 l – x

$x=\frac{5.7 \times 100}{12}=47.5 \;$ %

Answer: 47.5 %