creating a matrix with coefficients in this equation
"\\begin{vmatrix}\n 1 & 2& 1&5 \\\\\n 2 & 2& 1& 6\\\\\n1& 2&3 & 9\n\\end{vmatrix} \n(1) \n\n\n\n\n\n\n\\begin{vmatrix}\n 1 & 2& 1 \\\\\n 2 & 2& 1\\\\\n1& 2&3 \n\\end{vmatrix}\n(2)" finding determinan of matrix (2) A = -4
Replace the 1st column of the main matrix with the solution vector(5,6,9) and find its determinant
"\\begin{vmatrix}\n 5 & 2& 1 \\\\\n 6 & 2& 1\\\\\n9& 2&3 \n\\end{vmatrix}" B = -4
Replace the 2nd column of the main matrix with the solution vector and find its determinant
"\\begin{vmatrix}\n 1 & 5& 1 \\\\\n 2 & 6& 1\\\\\n1& 9&3 \n\\end{vmatrix}" C = -4
Replace the 3rd column of the main matrix with the solution vector and find its determinant
"\\begin{vmatrix}\n 1 & 2& 5 \\\\\n 2 & 2& 6\\\\\n1& 2&9 \n\\end{vmatrix}" D = -8
x=B/A=1
y=C/A=1
z=D/A=2
Solution set:
x=1
y=1
z=2
check
1*1+2*1+1*2 = 5
2*1+2*1+1*2 = 6
1*1+2*1+3*2 = 9
Comments
Leave a comment