"x^3 -25x^2- 4*x + 100 = 0"
imagine the left side as factors
"(x-2)(x-25)(x+2)=0"
each bracket may be equal 0. thats we have next three equations:
"x-2=0\\\\\nx-25=0\\\\\nx+2=0"
This equations have three roots: "x=2", "x=25", "x=-2"
This equation cannot be solved using the Cauchy-Schwartz inequality, since we have equality, and in the Cauchy-Schwarz inequality two variables are used, and we have one.
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