"F=k\\rho ^av^bA^c"
Here k is dimensionless constant, dimension of force "f" is "MLT^{-2}"
dimension of density "\\rho" is "ML^{-3}" , dimension of speed "v" is "LT^{-1}"
and dimension of surface area "A" is "L^2" .
So, dimensionally we have: "MLT^{-2}=(ML^{-3})^a(LT^{-1})^b(L^2)^c"
Equating the exponents on both sides of this equation leads to the system of linear equations:
"a=1,\\;\\;-3a+b+2c=1,\\;\\;-b=-2"
Solving this system we get: "a=1,\\;b=2,\\;c=1"
Therefore, the model will be: "F=k\\rho v^2A"
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