Question #103459

Suppose you are driving a van down a highway. Use dimensional analysis to find the wind force

you are experiencing, assuming that the force is affected by the wind density, the speed of the van

and its surface area exposed to the wind direction.

Expert's answer

F=kρavbAcF=k\rho ^av^bA^c

Here k is dimensionless constant, dimension of force ff is MLT−2MLT^{-2}

dimension of density ρ\rho is ML−3ML^{-3} , dimension of speed vv is LT−1LT^{-1}

and dimension of surface area AA is L2L^2 .

So, dimensionally we have: MLT−2=(ML−3)a(LT−1)b(L2)cMLT^{-2}=(ML^{-3})^a(LT^{-1})^b(L^2)^c

Equating the exponents on both sides of this equation leads to the system of linear equations:

a=1,    −3a+b+2c=1,    −b=−2a=1,\;\;-3a+b+2c=1,\;\;-b=-2

Solving this system we get: a=1,  b=2,  c=1a=1,\;b=2,\;c=1

Therefore, the model will be: F=kρv2AF=k\rho v^2A


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