Answer to Question #103459 in Algebra for mm

Question #103459
Suppose you are driving a van down a highway. Use dimensional analysis to find the wind force
you are experiencing, assuming that the force is affected by the wind density, the speed of the van
and its surface area exposed to the wind direction.
1
Expert's answer
2020-02-24T11:35:52-0500

F=kρavbAcF=k\rho ^av^bA^c

Here k is dimensionless constant, dimension of force ff is MLT2MLT^{-2}

dimension of density ρ\rho is ML3ML^{-3} , dimension of speed vv is LT1LT^{-1}

and dimension of surface area AA is L2L^2 .

So, dimensionally we have: MLT2=(ML3)a(LT1)b(L2)cMLT^{-2}=(ML^{-3})^a(LT^{-1})^b(L^2)^c

Equating the exponents on both sides of this equation leads to the system of linear equations:

a=1,    3a+b+2c=1,    b=2a=1,\;\;-3a+b+2c=1,\;\;-b=-2

Solving this system we get: a=1,  b=2,  c=1a=1,\;b=2,\;c=1

Therefore, the model will be: F=kρv2AF=k\rho v^2A


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