F=kρavbAc
Here k is dimensionless constant, dimension of force f is MLT−2
dimension of density ρ is ML−3 , dimension of speed v is LT−1
and dimension of surface area A is L2 .
So, dimensionally we have: MLT−2=(ML−3)a(LT−1)b(L2)c
Equating the exponents on both sides of this equation leads to the system of linear equations:
a=1,−3a+b+2c=1,−b=−2
Solving this system we get: a=1,b=2,c=1
Therefore, the model will be: F=kρv2A
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