Answer to Question #313206 in Abstract Algebra for Jyo

Question #313206

In (𝑍, +) , let 𝐻 = 𝑠𝑒𝑡 𝑜𝑓 𝑎𝑙𝑙 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑒𝑠 𝑜𝑓 3 and


𝐾 = 𝑠𝑒𝑡 𝑜𝑓 𝑎𝑙𝑙 𝑚𝑢𝑙𝑡𝑖𝑝𝑙𝑒𝑠 𝑜𝑓 5.


Show that H and K are subgroups of Z . Also describe 𝐻 ∩ 𝐾

1
Expert's answer
2022-03-18T01:12:59-0400

We shall show that H and K are closed under + and every element in H and K have their respective inverses in H and K




Let h,h°Hh,h°∈H . Then h=3kh=3k and h°=3qh°=3q , where k,qZk,q∈ℤ


h+h°=3k+3q=3(k+q)h+h°=3k+3q=3(k+q)


let k+q=mZk+q=m∈ℤ


Hence, H is closed under +


Let h° be the inverse of hHh∈H


=>h+h°=0=>h+h°=0 (identity element)


=>3k+h°=0=>3k+h°=0


=>h°=3k=3(k)=>h°=-3k=3(-k)


Let k=nZ-k=n∈ℤ


Thus, h°Hh°∈H


Hence, (H,+)(H,+) is a subgroup of (Z,+)(ℤ,+)





Let k,k°Hk,k°∈H . Then k=5rk=5r and k°=5qk°=5q , where r,qZr,q∈ℤ


k+k°=5r+5q=5(r+q)k+k°=5r+5q=5(r+q)


let r+q=mZr+q=m∈ℤ


Hence, K is closed under +



Let k° be the inverse of kHk∈H


=>k+k°=0=>k+k°=0 (identity element)


=>5r+k°=0=>5r+k°=0


=>k°=5r=5(r)=>k°=-5r=5(-r)


Let r=nZ-r=n∈ℤ


Thus, k°Hk°∈H


Hence, (K,+)(K,+) is a subgroup of (Z,+)(ℤ,+)



H∩K={z∈ℤ: z=15m, m∈ℤ}








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