the set of all functions of {1 2 3...,10} to itself forms a group w.r.t the composition of function.true or false
Consider the function
"f:\\{1, 2 \n,3,...,10\\}\\to\\{1 ,2, 3,...,10\\},"
"f(x)=1."
This function is not a bijection, and hence is not invertible. Therefore, "f" has no inverse, and we conclude that the set of all such functions does not form a group with respect to the operation of composition.
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