The element of S6 defined by f(1) = 3, f(2) = 4, f(3) = 1, f(4) = 5, f(5) = 6 and f(6) = 2 has the following representation by two-line notation:
"\\begin{pmatrix}\n1&2&3&4&5&6\\\\ 3&4&1&5&6&2\n \n\\end{pmatrix}" = (1 3) (2 4 5 6)
Explanation : Step 1:
we start with 1.1 goes to 3 and 3 goes back to 1 again. so first cycle is (1,3).
Step 2: we start second cycle with 2. 2 goes to 4, 4 goes to 5,5 goes to 6, 6 goes to 2 again. so second cycle is (2 4 5 6)
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