Let R be the ring and Rn={(x1.......xn)∣xi∈R} be the R-module.
Let us show that if I1,I2,...,In are ideals of R thenN=I1×I2×⋯×In={(x1,...,xn)∣xi∈I} is a submodule in Rn.
Taking into account that I1,I2,...,In are ideals of a ring R, we conclude that I1,I2,...,In are additive subgroups of a ring R, and therefore, N=I1×I2×⋯×In is a additve subgroup of Rn=R×R×⋯×R. Let r∈R and (a1,...,an)∈I1×I2×⋯×In be arbitrary. Since I1,I2,...,In are ideals of a ring R, ra1∈I1,...,ran∈In . Thus, r(a1,...an)=(ra1,...,ran)∈I1×I2×⋯×In , and we conclude that N is a submodule in Rn.
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