Answer to Question #141830 in Abstract Algebra for anjali

Question #141830
If M,N are R-module then M x N is also R-module
1
Expert's answer
2020-11-03T17:07:23-0500

M x N the following operations are set:

(m1,n1)+(m2,n2)=(m1+m2,n1+n2)r(m1,n1)=(rm1,rn1)rR, m1,m2M,n1,n2N(m_1,n_1)+(m_2,n_2)=(m_1+m_2,n_1+n_2)\\ r*(m_1,n_1)=(r*m_1,r*n_1)\\ r\in R,\ m_1,m_2\in M,n_1,n_2\in N

Since operations on M x N are "distributed" into two parts in M and N separately, it is quite obvious that M x N is an R-module. For example, let's check the commutativity:

(m1,n1)+(m2,n2)=(m1+m2,n1+n2)==(m2+m1,n2+n1)=(m2,n2)+(m1,n1)(m_1,n_1)+(m_2,n_2)=(m_1+m_2,n_1+n_2)=\\ =(m_2+m_1,n_2+n_1)=(m_2,n_2)+(m_1,n_1)


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