Let us consider the ideal J=11ZJ=11\mathbb ZJ=11Z of Z\mathbb ZZ. Then 1=12+(−11)∈12Z+11Z=I+J1=12+(-11)\in 12\mathbb Z +11\mathbb Z=I+J1=12+(−11)∈12Z+11Z=I+J. Since I+JI+JI+J is an ideal in Z\mathbb ZZ, a=1⋅a∈I+Ja=1\cdot a\in I+Ja=1⋅a∈I+J for any a∈Za\in\mathbb Za∈Z. Therefore, Z⊂I+J.\mathbb Z\subset I+J.Z⊂I+J. Taking into account that I+J⊂ZI+J\subset \mathbb ZI+J⊂Z, we conclude that I+J=Z.I+J=\mathbb Z.I+J=Z.
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