If A⊂B, prove that (A⋃C)⊂(B⋃C) for any set C.
If "A\u2282B" , prove that "(A\u22c3C)\u2282(B\u22c3C)" for any set "C" .
Let "A\u2282B" , take "x\\in (A\u22c3C)" then "x\\in A" or "x\\in C" and thus "x\\in B"
"\\implies" "x\\in A" , we can conclude that "(A\u22c3C)\u2282A"
If "x\\in A" , then simply by definition, "x\\in (A\u22c3C)"
"\\therefore A\u2282(A\u22c3C)" and hence "\\therefore A\u2282(A\u22c3C)"
"\\implies" "x\\in B" we can conclude that"(B\u22c3C)\u2282B"
If "x\\in B" , then by definition, "x\\in (B\u22c3C)" "\\iff B\u2282(B\u22c3C)" "\\implies \\therefore B\u2282(B\u22c3C)"
Hence the proof "(A\u22c3C)\u2282(B\u22c3C)"
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