Solution
If A⊂B , prove that (A⋃C)⊂(B⋃C) for any set C .
Let A⊂B , take x∈(A⋃C) then x∈A or x∈C and thus x∈B
⟹ x∈A , we can conclude that (A⋃C)⊂A
If x∈A , then simply by definition, x∈(A⋃C)
∴A⊂(A⋃C) and hence ∴A⊂(A⋃C)
⟹ x∈B we can conclude that(B⋃C)⊂B
If x∈B , then by definition, x∈(B⋃C) ⟺B⊂(B⋃C) ⟹∴B⊂(B⋃C)
Hence the proof (A⋃C)⊂(B⋃C)
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