The work supplied to a close system is given by:
A=∫v0vpdv=∫v0v(8+4v)dv=(8v+4v2)∣v0v=2v2+8v−2v02−8v0.
Substitute:
150⋅10−2=2v2+8v−2⋅1.62−8⋅1.6;
2v2+8v−19.42=0.
The obtained quadratic equation has the only positive root v=1.7027m3.
The final pressure of the system equals to:
P=8+4⋅1.7027=14.811bar.
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