Question #99679
To a closed system, 150kJ of work is supplied. If the initial volume is 1.6m^3 and the pressure of the system changes as P=(8+4v) P in bar and v in m^3, determine the fluid volume and pressure of the system
1
Expert's answer
2019-12-03T08:28:08-0500

The work supplied to a close system is given by:

A=v0vpdv=v0v(8+4v)dv=(8v+4v2)v0v=2v2+8v2v028v0.A=\int_{v_0}^{v}{pdv}=\int_{v_0}^{v}{(8+4v)dv}=(8v+4v^2)|_{v_0}^{v}=2v^2+8v-2v_0^2-8v_0.

Substitute:

150102=2v2+8v21.6281.6;150\cdot10^{-2}=2v^2+8v-2\cdot1.6^2-8\cdot1.6;

2v2+8v19.42=0.2v^2+8v-19.42=0.

The obtained quadratic equation has the only positive root v=1.7027m3.v=1.7027 m^3.

The final pressure of the system equals to:

P=8+41.7027=14.811bar.P=8+4\cdot1.7027=14.811 bar.


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