The work supplied to a close system is given by:
"A=\\int_{v_0}^{v}{pdv}=\\int_{v_0}^{v}{(8+4v)dv}=(8v+4v^2)|_{v_0}^{v}=2v^2+8v-2v_0^2-8v_0."
Substitute:
"150\\cdot10^{-2}=2v^2+8v-2\\cdot1.6^2-8\\cdot1.6;"
"2v^2+8v-19.42=0."
The obtained quadratic equation has the only positive root "v=1.7027 m^3."
The final pressure of the system equals to:
"P=8+4\\cdot1.7027=14.811 bar."
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