Question #81860

Calculate the maximum value of the e.m.f. generated in a coil which is rotating at 50 rev/s in a uniform
magnetic field of 0.8 Wb/m3
. The coil is wound on a square former having sides 5 cm in length and is wound
with 300 turns.
1

Expert's answer

2018-10-11T08:32:09-0400

Question #81860

Calculate the maximum value of the e.m.f. generated in a coil which is rotating at 50 rev/s in a uniform magnetic field of 0.8Wb/m30.8\mathrm{Wb} / \mathrm{m}^3. The coil is wound on a square former having sides 5 cm in length and is wound with 300 turns.

Answer:

The maximum value of the e.f.m. EmaxE_{max} is given by


Emax=BANω,E _ {m a x} = B A N \omega ,


where B=0.8Wb/m3B = 0.8\mathrm{Wb / m}^3 – flux density of the magnetic field,

N=300N = 300 – number of the coil,

A=5×5cm2=0.0025m2A = 5 \times 5 \, \text{cm}^2 = 0.0025 \, \text{m}^2 – the area of the coil,

ω=50rev/s=100πrad/s\omega = 50 \, \text{rev/s} = 100\pi \, \text{rad/s} – the rotational speed of the coil.

Substitute into (1):


Emax=0.80.0025300100π=188.5V.E _ {m a x} = 0. 8 \cdot 0. 0 0 2 5 \cdot 3 0 0 \cdot 1 0 0 \pi = 1 8 8. 5 \, \text{V}.

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