A riveted joint is shown in the figure which is used in the bridge to lock the wire, By using the information from the Figure you have to calculate the maximum bearing stress available between the pin and the members of the joint; You also need to calculate (b) the average shear stress in the pin for given load; as well as (c) the maximum mean normal stress in the joint members.
So that normal express not to be more than 1 50 mega bhaskar and Sierra's press not to be more than 16 mega pascal Member Cp has the square cross section. Remember CB having a square cross section bit 25 millimeters site applying the condition of equilibrium alpha. You can find Canon worse off two up 1 1.5. That is 53.13° Finding Couple at 8 0. You will get -B into 1.5 Plus B. X. and put to scale to zero. So the taxi will get .75 B. No couple at sea must be zero. So you can write be way into 1.5 -7. X. is culture too. So be why you will get P. No submission of fx Must be zero at 1 c. 4.75 p. 53.13. But this piece I know 53.13 normal force at section A. It's a normal force at section A. You will get 1.25 p. No submission of fy two V zero. So you can write .75 times being Sign of 53.13 minus because of 53.13 minus sheer force. Those years Force on the section A will be zero India prosection will be sided square. That is .025 square. So 6.25 into 10 to the power -4 m square. No sigma is N. A. And its maximum value is This is given 150 and it's 1.25 p upon 6.25 10 to the power minus force. So maximum value of p. You will get 75 kN.
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