Question #322876

a welded joint, as shown in fig. is subjected to an eccentric load of 2500 n. find the size of the weld, if the maximum shear stress in the weld is not to exceed 50 n/mm^2

Expert's answer

Weld area :

A=PσA = \frac{P}{\sigma }

A=250050=50mm2A = \frac{2500}{50}=50 mm^2

A=t×lA = t \times l

Throat thickness t=5010=5mmt =\frac{50}{10}=5mm

Size of weld s=tks = \frac{t}{k}

s=50.7=7.14mm≈8mms = \frac{5}{0.7} =7.14 mm \approx 8 mm



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