Question

3. A 4.3in diameter by 3in long journal bearing is to carry a 6600lb load at 4600

r[, isomg SAE 40 lube oil at 200 through a single hole at 25 psi. Compute

the bearing pressure. Bearing pressure is the same as bearing stress.

( Ans Sb=511.63psi )

Answer 1

bearing preasure due to load=$\frac{load}{area}$

$=\frac{6600}{4.3*3}=511.6279$

=511.63psi