Question #320831

1. A steel tie rod on bridge be made withstand a pull of 3500lbs. find the

diameter of the rod assuming a factor of safety of 2.5 and ultimate stress of

5700psi.


( Ans d=1.398 in. )



1
Expert's answer
2022-03-31T02:46:01-0400

A=KPσA=\frac{KP}{\sigma}

=2.535005700=175114=\frac{2.5*3500}{5700}=\frac{175}{114}

A=π4D2A=\frac{\pi}{4}*D^2

175114=π4D2\frac{175}{114}=\frac{\pi}{4}*D^2

D2=1754114π=1.9545D^2=\frac{175*4}{114*\pi}=1.9545

D=1.398in.


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