Answer to Question #312999 in Mechanical Engineering for ali

Question

How much product at 10% wet basis moisture would you obtain from drying 3.5 kg of carot (89% moisture)?

Answer 1

Weight of water at start = 3.5 kg × 0.85 = 2.975 kg

% solids at start = 100% - 85% = 15%

Weight of solids at start = 3.5 kg × 0.15 = 0.525 kg

Weight of solids in the final product = Weight of solids in the starting product = 0.525 kg

Since the final product contains 10% moisture by weight, it will contain 90%

solids.

Let X be the weight of the final product

0.90X = 0.525 kg

X = 0.583 kg