11. A 100 BHP diesel engine has a brake thermal efficiency of 30% and jacket water loss of 34%. The engine is to be cooled by means of a cooling tower having a range of 27oC. Find the mass of water leaving the tower.
QOut=η×Qin=0.3×74.57=22.37kWQ_{Out} = \eta \times Q_{in}=0.3\times 74 .57 = 22.37 kWQOut=η×Qin=0.3×74.57=22.37kW
mass of water leaving the tower.
Qout=m×Cp×△TQ_{out}= m\times C_p\times \triangle TQout=m×Cp×△T
m=223701×300=74.56kgm = \frac{22370}{1\times300}=74.56kgm=1×30022370=74.56kg
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