Answer to Question #309442 in Mechanical Engineering for Jhonny

Question

2. A Rankine cycle has an initial mass of liquid flowing at 10 kg at 75℃. If final enthalpy is 379.6 KJ, find the change of the system.

Answer 1

For pt₁ t=75℃ h₁= 313.93 kJ/kg

for pt₂ h₂ = 379.6 kJ/kg

∆h = (h₂ − h₁) = (379.6 - 313.93) = 65.67 kJ/kg

∆H = 65.67 kJ/kg × 10 kg = 656.7 kJ