Answer to Question #305226 in Mechanical Engineering for Jul

Question

2. Two parallel shafts connected by rolling cylinders turn in the same direction 150 rpm and 100 rpm respectively. The smaller cylinder is 16 in. in diameter. How far apart are the axes of the shafts? Please explain the answer.

Answer 1

$D_1N_1 = D_2N_2$

$D_2=\frac{150\times16}{100}= 24$ in

 For the same direction

distance, C

$C =\frac{D_2-D_1}{2}=\frac{24-16}{2} = 4$  in