Question #298102

A triaxial stress element as shown in Figure has σx = 40 MPa, σy = –20 MPa, σz = –10 MPa, τxy = 5 MPa, τyx = –1.5 MPa, τzx = 2.5 MPa. Answer following questions:





Find the principal stresses using a numerical method (i.e., using Eigen values method) and draw the resulting Mohr’s circles. (You can use Scientific Calculator for calculating eigen values of the stress matrix)





Draw the resulting Mohr's circles.

1
Expert's answer
2022-02-16T05:59:03-0500

Mohr's circle is a graphical representation of the transformation equations for plane stress problems. It is useful in visualizing the relationships between normal and shear stresses acting on a stress element at any desired orientation.

principal stresses

σ1,  σ2=σx+  σy2±(σx  σy2)2+(τxy)2{{\rm{σ }}_1},\;{{\rm{σ }}_2} = \frac{{{{\rm{σ }}_x} + \;{{\rm{σ }}_y}}}{2} \pm \sqrt {{{\left( {\frac{{{{\rm{σ }}_x} - \;{{\rm{σ }}_y}}}{2}} \right)}^2} + {{\left( {{τ _{xy}}} \right)}^2}}


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