Question #297239

Direct stresses of 120 N/mm^2 (tension) and 90 N/mm^2 (compression) are applied at a particular point in an elastic material on two mutually perpendicular planes the principal

stress in the material is limited to 100 N/mm^2(tension) calculate the allowable value of shear stress at the point on the given planes determine also the value of the other principal stress and the maximum value of shear stress at the point using Mohr's circle


1
Expert's answer
2022-02-16T04:48:02-0500

σx=120MN/m2(tensilei.e+ive)σx = 120MN/m2 (tensile i.e + ive)


σy=90MN/m2σy = 90MN/m2

(Compressivei.e.ive)(Compressive i.e. – ive)  

τxy=?τxy = ?

σ1=150MN/m2σ1 = 150MN/m2  Since we have

150=½[(12090)+(120(90))2+4(τxy)21/2]150 = ½[(120 – 90) + {(120 – (– 90))2 + 4(τxy)2}1/2]

τxy=84.85MN/m2τxy = 84.85MN/m2  Now the magnitude of other principal stress

σ2σ2=½[(12090)(120(90))2+4(84.85)21/2]σ2 σ2 = ½[(120 – 90) – {(120 – (– 90))2 + 4(84.85)2 }1/2]

σ2=120MN/m2σ2 = – 120MN/m2  

The direction of principal planes is:

tan2θ=2τxy/(σxσy)tan 2θ = 2 τxy / (σx −σy)  

tan2θ=(2×84.85)/(120(90))tan 2θ = (2 × 84.85)/(120 – (– 90))

2θ=38.94ºor2218.94ºθ2θ= 38.94º or 2218.94º θ

19.47ºor109.47º19.47º or 109.47º


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